1. Tin and oxygen gas are reacted together to form Tin (IV) oxide, a solid. If a piece of tin foil, 8.25cm x 21.5cm x 0.60mm (density = 7.28g/cm3) is exposed to oxygen and all the tin reacts, what is the mass of the oxidized tin foil? (98.4g)
I am so confused on this problem the answer is 98.4 but can anyone show me how to get to that answer??????
Step 1. Write and balance the equation.
Sn + O2 ==> SnO2
Step 2. How much Sn do you have? You can find the volume (length x width x thickness but change the thickness of 0.60 mm tp 0.060 cm so that all of the units will be the same). Now you know
mass = volume x density. You now have the density and the volume in cm^3 so you can calculate the mass.
Step 3. Convert mass to moles. # moles Sn = grams Sn/molar mass Sn.
Step 4. Using the coefficients in the balanced equation, convert moles Sn to moles SnO2.
Step 5. Now convert moles SnO2 to grams SnO2. grams SnO2 = moles SnO2 x molar mass SnO2.
I didn't do the math but if you don't get the answer, either the answer is wrong or you slipped up somewhere. Post your work if that happens and I'll find the error. Good luck.
To solve this problem, you need to calculate the mass of the tin foil and then determine the amount of tin that reacts in the chemical reaction with oxygen. By subtracting the mass of the remaining tin from the initial mass, you can find the mass of the oxidized tin foil.
Here's a step-by-step guide to solve the problem:
1. Calculate the volume of the tin foil:
Volume = length x width x height
Volume = 8.25cm x 21.5cm x 0.60mm (convert mm to cm by dividing by 10)
2. Convert the volume to mass using density:
Mass = Volume x Density
3. Determine the molar mass of tin (Sn) and tin (IV) oxide (SnO2):
Consult the periodic table for the molar masses:
Molar mass of Sn = 118.71 g/mol
Molar mass of SnO2 = 150.71 g/mol
4. Calculate the moles of tin in the tin foil:
Moles of Sn = Mass of Sn / Molar mass of Sn
5. Use stoichiometry to relate the moles of tin to moles of SnO2 in the chemical reaction:
The balanced chemical equation is: Sn + 2O2 -> SnO2
From the equation, 1 mole of Sn reacts with 2 moles of O2 to produce 1 mole of SnO2.
6. Calculate the moles of SnO2 produced:
Moles of SnO2 = Moles of Sn / 1 (according to the stoichiometry of the reaction)
7. Calculate the mass of the SnO2 formed:
Mass of SnO2 = Moles of SnO2 x Molar mass of SnO2
8. Subtract the mass of the remaining tin from the initial mass to find the mass of the oxidized tin foil:
Mass of oxidized tin foil = Initial mass - Mass of SnO2
Following these steps, you should obtain the correct answer of 98.4g.