Militsa has 4 times as many nickels as dimes. Their total value is $8.10. How many of each coin does she have

Let N be the number of nickels and D be the number of dimes. Here is what you know:

N = 4D
10D + 5N = 810
-----------------
Now substitute 4D for N

10D + 20D = 810

30D = 810
You take it from there

30D=810 check

=D=810/30 108*.05+27*.1=8.1
=D=27 5.4+2.7=8.1
8.1=8.1
x=y*4
x=27*4
x=108

y=27

85

jk idk how

Let's solve this problem by breaking it down into steps. First, let's assign variables to the unknowns in the problem. Let's call the number of dimes "x" and the number of nickels "y".

Given that Militsa has 4 times as many nickels as dimes, we can express this relationship as y = 4x.

Next, we can determine the value of the coins. A dime is worth $0.10, so the total value of the dimes is 0.10x. Similarly, a nickel is worth $0.05, so the total value of the nickels is 0.05y.

The problem states that the total value of the coins is $8.10, so we can create an equation based on this information:

0.10x + 0.05y = 8.10

Now, we can substitute y = 4x into the equation to eliminate the variable y:

0.10x + 0.05(4x) = 8.10

Simplifying:

0.10x + 0.20x = 8.10

0.30x = 8.10

Dividing both sides of the equation by 0.30:

x = 27

Now that we know the value of x, we can substitute it back into the equation y = 4x to find the value of y:

y = 4(27)
y = 108

Therefore, Militsa has 27 dimes and 108 nickels.