Li2CO3+HBr->

I don't know what you want.
Li2CO3 + HBr ==> LiBr + H2O + CO2
You will need to balance it

Li2Co3+2HBr->H2Co3+2LiBr
then you seprate
Li(aq)+1 + Co3(aq)+2 + 2H(aq)+1 + 2Br(aq)+1 --> H(aq)+1 + Co3 (aq)+2 + 2Li(aq)+1 + 2Br(aq)+1
then cancel out
Co3(aq)+2 and 2Br(aq)+1

I thought that's what the problem had in mind BUT
first, CO3 is -2 and not +2.
Second, H2CO3, if that is the way you want to leave it, is a weak acid and does not ionize (only slightly); therefore, it doesn't produce H^+ and CO3^-2 ions so no canceling takes place.
Third, Li2CO3 by itself doesn't show any water there so no (aq) solution can be formed. The way your original post was stated I would write it as Li2CO3(s).
Li2CO3(s) + 2HBr(aq) ==> 2LiBr(aq) + H2CO3(aq)

Li2CO3(s) + 2H^+(aq) + 2Br^-(aq) ==> 2Li^+(aq) + 2Br^-(aq) + H2CO3(aq).
And to be accurate, you should then show the decomposition of H2CO3 as
H2CO3(aq) ==> H2O(l) + CO2(g)

youre wrong!!

can you help me or not??

Sorry 'bout that. I calls 'em the way I sees 'em. There may be a mix up in the way I have interpreted the problem or perhaps you did not post exactly what you meant to post. I don't know what part you think is incorrect since I objected to a number of items in your post but I shall be happy to hear what you think is incorrect, in detail.

start over and show me again not sloppy please

I'm never sloppy. Post the rules you are following so we can follow the same set of rules.

too many...shouldnt they all be the same though?

ugh..why is chemistry so difficult

Yes, they SHOULD be the same; however, from your previous comments, it is apparent to me that you are following one set of rules and I'm following a different set of rules. Hence, if we are to proceed we should agree on the rules we are using. Otherwise, you won't trust any of my answers. :-).

Chemistry isn't difficult. It's the people that make it hard.

fatty

well then you make it hard because you think your so smart then you sit here and say well there are dfferent rules the say no there are only one set of rules...is there someone else that can help me with my homework..

??

so is there anyone else???

thanks for the help kinda maybe you should read a science book some time and not lie to students in nedd of help you...

what are set ionic equation

chemistry question

Ionic equations are equations that show the reaction between two ionic compounds. They are written in the form of a balanced chemical equation, with the ions represented as subscripts. For example, the reaction between sodium chloride and silver nitrate can be written as:
NaCl + AgNO3 → NaNO3 + AgCl

A set ionic equation, also known as a complete ionic equation, is a chemical equation that shows all the ions present in a reaction. It represents the dissociation of all soluble compounds into their respective ions. This type of equation is commonly used to describe reactions that occur in aqueous solutions.

To write a set ionic equation, you follow these steps:

1. Write the balanced molecular equation for the reaction.
2. Dissociate any soluble compounds into their respective ions.
3. Write each ion separately, indicating their charges.
4. Include state symbols (s, l, g, or aq) for each substance, indicating whether it is a solid, liquid, gas, or aqueous solution.

For example, let's consider the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3):

NaCl(aq) + AgNO3(aq) -> AgCl(s) + NaNO3(aq)

To write the set ionic equation, we first need to dissociate the compounds that are soluble:

Na+(aq) + Cl-(aq) + Ag+(aq) + NO3-(aq) -> AgCl(s) + Na+(aq) + NO3-(aq)

In this equation, the sodium ions (Na+) and nitrate ions (NO3-) remain the same on both sides of the equation, so they are called spectator ions. The silver ions (Ag+) and chloride ions (Cl-) are involved in the formation of the precipitate (AgCl) and are considered the main players in the reaction.

I hope this helps! Let me know if you have any other questions.

I'm sorry if my previous responses were not helpful. I am here to assist you with your questions. A set ionic equation is a way to represent a chemical reaction by showing the dissociation of all the ions involved in the reaction. It is commonly used in chemistry to understand the chemical reaction at a molecular level.

To write a set ionic equation, you need to follow a few steps:

1. Write the balanced chemical equation for the reaction.
2. Identify which compounds are soluble in water and will dissociate into ions.
3. Separate these compounds into their respective ions, indicating their charges.
4. Cancel out any spectator ions that appear on both sides of the equation.

For example, let's consider the reaction:

NaCl(aq) + AgNO3(aq) -> AgCl(s) + NaNO3(aq)

Step 1: The balanced chemical equation is already given.

Step 2: In this case, all the compounds in the equation are soluble in water and will dissociate into ions.

Step 3: Rewrite the equation, separating the compounds into their respective ions:

Na+(aq) + Cl^-(aq) + Ag+(aq) + NO3^-(aq) -> AgCl(s) + Na+(aq) + NO3^-(aq)

Step 4: Cancel out any spectator ions that appear on both sides of the equation:

The final set ionic equation is:

Ag+(aq) + Cl^-(aq) -> AgCl(s)

I hope this explanation helps. If you have any further questions, please let me know.