Please help me!!!!!!!!!!!!!!!1

Instructions

a. If needed, rewrite the following equations in slope-intercept form. *

b. Indicate the slope and the y-intercept for each of the equations.

c. Using graph paper and a straight edge, graph the equations.

1. y = 3x − 4

2. 2x + 3y = 6

3. y + 3 = 0

4. x − 6 = 9

*Hint: One of the equations is already in slope-intercept form and one of the equations cannot be written in this form.

Instructions

a. If needed, rewrite the following equations in slope-intercept form. *

b. Indicate the slope and the y-intercept for each of the equations.

c. Using graph paper and a straight edge, graph the equations.

1. y = 3x − 4
This one is in slope intercept form. (y=mx+b)

Solve for x and y in the equation, then graph.

2. 2x + 3y = 6
Put this one in slope intercept form. y=mx+b
Then, or course solve for x and y and graph.

3. y + 3 = 0
Cannot be in slope intercept.

4. x − 6 = 9
Cannot be in slope intercept.

How do I put it in slope intercept form?

2. Subtract 2x from both sides and then divide both sides by 3.

I hope this helps a little more. Thanks for asking.

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To put the equation 2x + 3y = 6 in slope-intercept form (y = mx + b), you need to isolate the y variable.

1. Start by subtracting 2x from both sides of the equation:
2x + 3y - 2x = 6 - 2x
3y = -2x + 6

2. Next, divide both sides by 3 to solve for y:
(3y)/3 = (-2x + 6)/3
y = (-2/3)x + 2

Now the equation is in slope-intercept form. The slope, represented by m, is -2/3, and the y-intercept, represented by b, is 2.

To graph this equation, plot the y-intercept, which is the point (0, 2). Then, use the slope to find other points. The slope of -2/3 indicates that for every increase of 3 units in the x-direction, the y-coordinate decreases by 2 units. Use this information to plot additional points and draw a straight line passing through them.