What charge in coulombs is required to deposit 0.301g Cu(s) from a solution of Cu^2+?

Cu^2+ 2e^- = Cu

0.301g/63.5g/mol = 4.7 x 10^-3 mol Cu

(4.7 x 10^-3 mol Cu) (2 mol e^-/mol Cu)

I should be able to mutiply that by 96,500 (Faraday number) to get 914C, but I don't.

Someoneoffered me a number of Coulombs per electron of 1.602x10^-19.

What's the difference between Coulombs per electron and 1 Faraday?

1 answer

  1. 0.301/63.54 x 2 x 96,484 = 914.1 which rounds to 914. Perhaps you're punching the wrong numbers on the calculator.

Answer this Question

Still need help?

You can ask a new question or browse more Inorganic chemistry questions.