Given the following neutralization raction: HCO3^- + OH^- <=> CO2[over]3^- + H2O
a. label the conjugate acid-base pairs in this system
b. is the forward or reverse reaction favored? Explain.
Write net ionic equations that represent the following ractions:
a. the ionization of HClO3 in water
b. NH3 functioningas an Arrhenius base
Calcium selenate has the formula CaSeO4
a. what is the formula for selenic acid?
b. what is the formula for selenous acid?
H2SO3 -> H^+ + HSO3^-
HSO3^- -> H^+ + SO3^-2
Which stage of ionization is favored? Explain your answer in terms of relative acid strength.
You would do well to post one question per post. It makes it easier that way. Also, we don't do homework but we help. Please indicate what you think the answers are and why you think that way. For the first one, remember the definitions. HCO3^- must be giving away its proton for it ends up on the other side as CO3^=. So HCO3^- must be an acid and its conjugate base is CO3^=.
sorry, its my first time using this website. thanks for the help though
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No problem! I'm here to help. Let's go through the questions one by one.
Given the neutralization reaction: HCO3^- + OH^- <=> CO2^-3 + H2O
a. To identify the conjugate acid-base pairs, we need to determine which species donates a proton (acid) and which species accepts a proton (base). In this reaction, HCO3^- donates a proton to OH^- and becomes CO2^-3, while OH^- accepts a proton and becomes H2O. Therefore, the conjugate acid-base pairs in this system are HCO3^-/CO2^-3 and OH^-/H2O.
b. To determine whether the forward or reverse reaction is favored, we need to consider the equilibrium position. In a neutralization reaction, the forward reaction is favored when the acid is stronger and the reverse reaction is favored when the base is stronger. Since HCO3^- is a weaker acid compared to OH^-, the reverse reaction is favored.
Now let's move on to the next set of questions:
a. The ionization of HClO3 in water can be represented by the following net ionic equation:
HClO3(aq) + H2O(l) -> H3O+(aq) + ClO3^-(aq)
b. NH3 can function as an Arrhenius base by accepting a proton (H+) from water. The net ionic equation for the ionization of NH3 in water is:
NH3(aq) + H2O(l) -> NH4+(aq) + OH^-(aq)
Next, let's tackle the questions about formulas:
a. The formula for selenic acid is H2SeO4. By convention, for oxyacids, the number of hydrogen atoms in the formula is determined by the charge of the anion (-1 for SeO4^2-).
b. The formula for selenous acid is H2SeO3. Similar to selenic acid, the number of hydrogen atoms is determined by the charge of the anion (-1 for SeO3^2-).
Finally, let's analyze the ionization stages:
H2SO3 -> H+ + HSO3^-
HSO3^- -> H+ + SO3^2-
In terms of relative acid strength, since H2SO3 loses one proton to become HSO3^-, and then HSO3^- loses another proton to become SO3^2-, we can conclude that the first stage of ionization is favored. This is because H2SO3 is a stronger acid compared to HSO3^-. The stronger the acid, the more likely it is to dissociate and donate a proton.