4x-2y-6=0 (1,1)

put the line in slope intercept form y=mx+b then,you know the slope of the perpendicular line is the negative reciprocal of m (new slope of perpendicular line=-1/m So for the perpendicular line... y=-1/m x + b put in the point 1,1 1=-/m + b you know m, solve for b.

there is a little formula for this question: for Ax + By + C = 0 the distance from a point (p,q) to that line is │Ap + Bq + C│/√(a^2+b^2) so distance = │4-2-6│/√(16+4) = 4/√20 = 4√20 /20 = 4√5/5

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