What would be the pressure on the skin of a scuba diver is he dives under the ocean at 30m below the water surface? The density of the sea water is about 1030 kg/m3. The atmospheric pressure is standard at 1.013 x 105 Pa.
The pressure on the skin of the scuba diver at a depth of 30m can be calculated using the formula:
P = ρgh + Patm
where P is the total pressure, ρ is the density of the water, g is the acceleration due to gravity, h is the depth, and Patm is the atmospheric pressure.
Plugging in the values, we get:
P = (1030 kg/m3) x (9.81 m/s2) x (30m) + 1.013 x 105 Pa
P = 29226 + 1.013 x 105
P = 1.342 x 105 Pa
Therefore, the pressure on the skin of the scuba diver at a depth of 30m below the water surface is 1.342 x 105 Pa.
When a submarine dives to a depth of 100m , to how large a total pressure is its exterior surface subjected? The density of the sea water is about 1030 kg/m3. The atmospheric pressure is standard at 1.013 x 105 N/m2.
The total pressure on the exterior surface of a submarine at a depth of 100m can be calculated using the formula:
P = ρgh + Patm
where P is the total pressure, ρ is the density of the water, g is the acceleration due to gravity, h is the depth, and Patm is the atmospheric pressure.
Plugging in the values, we get:
P = (1030 kg/m3) x (9.81 m/s2) x (100m) + 1.013 x 105 N/m2
P = 101307 + 1.013 x 105
P = 2.046 x 105 N/m2
Therefore, the exterior surface of the submarine is subjected to a total pressure of 2.046 x 105 N/m2 at a depth of 100m.
Atmospheric pressure is about 1.0 x 105 Pa. How large a force does the still air in the room exert on the inside of a window pane that 60cm x 120cm?
The force exerted by the still air in the room on the inside of the window pane can be calculated using the formula:
F = PA
where F is the force, P is the pressure, and A is the area.
Plugging in the values, we get:
F = (1.0 x 105 Pa) x (0.6m x 1.2m)
F = 72,000 Pa
Therefore, the still air in the room exerts a force of 72,000 Pa on the inside of the window pane. Note that Pa (Pascals) are equivalent to N/m2 (Newtons per square meter), so the force can also be expressed as:
F = 72,000 N/m2
To calculate the pressure on the skin of a scuba diver at a certain depth below the water surface, you need to consider the water pressure and the atmospheric pressure. Here's how you can calculate it:
1. Determine the water pressure:
The pressure in a fluid (such as water) increases with depth due to the weight of the fluid above it. This can be calculated using the formula:
Pressure = Density × Gravity × Depth
In this case, the density of seawater is given as 1030 kg/m3, and the depth is 30m. The acceleration due to gravity (g) is approximately 9.8 m/s2.
So, the water pressure at a depth of 30m is:
Pressure_water = 1030 kg/m3 × 9.8 m/s2 × 30m
2. Calculate the total pressure:
The pressure at any point under the water is the sum of the water pressure and the atmospheric pressure. The atmospheric pressure at sea level is standard at 1.013 x 105 Pa.
So, the total pressure on the skin of the scuba diver at a depth of 30m would be:
Pressure_total = Pressure_water + Atmospheric pressure
Simply substitute the calculated values for the variables and perform the addition to find the answer.
Note: The unit of pressure used here is Pascal (Pa).