what are the four quantum numbers of the last electron of As
this is what i have
n=4
l=1
ms= 1/2
i don't know how to calculate ml. I know it's either: -1,0,1
Here is a site that gives the electron configuration showing
3d10 4s2 4p3.
Thus for the last electron, that will be the one that is 4p and I usually fill the -1, then 0, then +1 for ml. You are correct on n, ms and and l.
so it will be 1 as the last electron comes on that one correct?
umm and i don't see the link you posted :S
You didn't see it because I didn't post it. Sorry about that.
http://www.webelements.com/arsenic/atoms.html
Yes, 1 for ml is what I would do.
To calculate the ml (magnetic quantum number) of the last electron of an atom, you need to know the value of l (azimuthal quantum number). In the case of the last electron of arsenic (As), you correctly identified n (principal quantum number) as 4 and l (azimuthal quantum number) as 1.
The ml values are determined by the formula ml = -l, -(l-1), ..., 0, ..., (l-1), l. Since l = 1, we can substitute it into the formula to find the possible ml values.
ml = -l, -(l-1), ..., 0, ..., (l-1), l
= -1, 0, 1
Therefore, the possible ml values for the last electron of arsenic can be -1, 0, or 1.
So, the four quantum numbers of the last electron of As are:
n = 4 (principal quantum number)
l = 1 (azimuthal quantum number)
ml = -1, 0, 1 (magnetic quantum number)
ms = 1/2 (spin quantum number)