[mole-mole]
How many moles of NaOH are needed to react with 5.0 moles of sulfuric acid, H2SO4???
Equation: H2SO4 + 2 NaOH ---> Na2 SO4 +2 H2 O
Two moles of lye is needed for each mole of acid.
Thats how its on the paper !
c2h5oh(l)302(g)>3h2o{L}
To determine the number of moles of NaOH needed to react with 5.0 moles of H2SO4, we need to use the balanced chemical equation.
From the equation, we can see that for every 1 mole of H2SO4, we need 2 moles of NaOH to react. This means that the mole ratio between H2SO4 and NaOH is 1:2.
Given that we have 5.0 moles of H2SO4, we can set up a proportion to find the moles of NaOH:
(5.0 moles H2SO4) / (1 mole H2SO4) = (x moles NaOH) / (2 moles NaOH)
Cross-multiplying, we get:
5.0 moles H2SO4 * 2 moles NaOH = x moles NaOH * 1 mole H2SO4
10.0 moles NaOH = x moles NaOH
Therefore, 10.0 moles of NaOH are needed to react with 5.0 moles of sulfuric acid, H2SO4.