Gravity and Air Resistance Quick Check

connexus 10th grade physical science

all of these are correct as of 2/4/23 :)

1. What happens when a falling object reaches terminal velocity?
💗- it stops accelerating.

2. How does a falling object's surface area effect calculations of terminal velocity?
💗- The greater the object's surface area, the more air resistance it encounters.

3. Which is the equation for terminal velocity?
💗- Vt = √2w÷dACᵈ

4. A ball falls from a tall bridge. The ball has a mass of 0.15 kg. The air density is 1.225 kg/m³. The ball's surface area is 0.0026 m². The ball's coefficient of drag is 0.007. What is the ball's terminal velocity?
💗- 363 m/s

5. Hanna wants to calculate the terminal velocity of a typical meteorite just before it hits Earth. She researches meteorites at the library and on the internet. What information does she need to find?
💗- a typical meteorite's weight, surface area, and coefficient of drag; air density close to Earth.

hope this helped <3

100 percent correct tysm

Great job! Your answers are correct. It seems like you understand the concept of terminal velocity and how it is affected by factors such as surface area and air resistance. If you have any more questions, feel free to ask!

Great job on the quick check! You got all the answers correct. Here's a breakdown of how you can find the answers to each question, in case you need to do similar calculations or research in the future:

1. To determine what happens when a falling object reaches terminal velocity, you need to understand that terminal velocity is the maximum velocity that an object can reach while falling. At this point, the gravitational force pulling the object downward is balanced by the opposing force of air resistance (also known as drag). As a result, the object stops accelerating and continues to fall at a constant velocity.

2. The surface area of a falling object affects calculations of terminal velocity because it influences the amount of air resistance the object encounters. The larger the surface area of the object, the more air molecules it will collide with, leading to greater air resistance. This increased resistance can ultimately impact the object's rate of acceleration and its terminal velocity.

3. The equation for terminal velocity is Vt = √(2w÷(dACᵈ)), where Vt represents the terminal velocity, w is the weight of the object, d is the air density, A is the surface area of the object, and Cᵈ is the coefficient of drag. This equation provides a way to calculate the terminal velocity based on the given parameters.

4. To calculate the ball's terminal velocity, you can use the formula mentioned earlier: Vt = √(2w÷(dACᵈ)). Plug in the values given in the question: w = 0.15 kg, d = 1.225 kg/m³, A = 0.0026 m², and Cᵈ = 0.007. By substituting these values into the equation and solving it, you should find that the ball's terminal velocity is 363 m/s.

5. To calculate the terminal velocity of a meteorite, Hanna would need to gather specific information about the meteorite itself and the environment (air density) close to Earth. The required information includes the meteorite's weight, surface area, and coefficient of drag. With these values, along with the air density close to Earth, Hanna can use the terminal velocity equation (Vt = √(2w÷(dACᵈ))) to calculate the terminal velocity of the meteorite.

I hope this breakdown helps you better understand how to find these answers. Keep up the good work! If you have any more questions, feel free to ask.