ok so i have these 3 problems:
1. 2(5x + 4) + 3 + x = 10x + 46
2. -(3y + 4) - 6y + 5 = -9y + 1
3. -2z + 5 - z + 6 = -3z + 11
for x, i got 35,
for y, i got 0,
and for z, i got 0 as well.
I want to know if these are all correct, and if one or more answers aren't correct, plz lmk! thank u to those who help <3
i had to do these problems too omg
for #2, the equation holds for any value of y
-(3y + 4) - 6y + 5 = -9y + 1
-3y-4-6y+5 = -9y+1
-9y+1 = -9y+1
same for #3.
To check your solutions for each variable, we will substitute them into the original equation and verify if both sides of the equation are equal.
1. 2(5x + 4) + 3 + x = 10x + 46
Substitute x = 35
2(5(35) + 4) + 3 + 35 = 10(35) + 46
Simplify both sides of the equation:
2(175 + 4) + 3 + 35 = 350 + 46
2(179) + 3 + 35 = 396
358 + 3 + 35 = 396
358 + 38 = 396
396 = 396
Both sides of the equation are equal, so x = 35 is correct.
2. -(3y + 4) - 6y + 5 = -9y + 1
Substitute y = 0
-1(3(0) + 4) - 6(0) + 5 = -9(0) + 1
Simplify both sides of the equation:
-1(0 + 4) - 0 + 5 = 0 + 1
-1(4) + 5 = 1
-4 + 5 = 1
1 = 1
Both sides of the equation are equal, so y = 0 is correct.
3. -2z + 5 - z + 6 = -3z + 11
Substitute z = 0
-2(0) + 5 - 0 + 6 = -3(0) + 11
Simplify both sides of the equation:
0 + 5 - 0 + 6 = 0 + 11
5 + 6 = 11
11 = 11
Both sides of the equation are equal, so z = 0 is correct.
Therefore, all your solutions are correct: x = 35, y = 0, and z = 0.