A uniform capillary closed at one end Contained dry air trapped by a thread of mecury 8.5×10^_2 long When The tube Was Held Horizontally the length of air column was 5.0×10^_2 when it was held vertically with the closed end downwards the length was 4.5×10^_2 determine the value of the atmospheric pressure. ( g=10ms^_2 density of mercury 1.36×10^4
kgm^_3)
Atmospheric pressure = (density of mercury x g x (length of mercury column - length of air column)) / (length of air column)
Atmospheric pressure = (1.36 x 10^4 x 10 x (8.5 x 10^2 - 5.0 x 10^2)) / (5.0 x 10^2)
Atmospheric pressure = 1.05 x 10^5 Pa