You have five $1 bills, four $5 bills, six $10 bills, and three $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?

That answer by the bot is wrong of course!!!!

Prob(1) = 5/18
so there are 17 left
prob(10) = 6/17

prob(1, then 10) = (5/18)(6/17) = 5/51 = appr .098

P($1, then $10) = 5/18 = 0.2777 or 27.77%