Find an equation of the line containing the give pair of points.

(-2, -1), and (-7,-4)
The equation of the line in slope-intercept from is y= what

The slope is

m = (y2-y1)/(x2-x1)
= [-4 -(-1]/[-7-(-2)]
= -3/-5 = 3/5

The equation will be of the form
y = (3/5) x + b
Use the coordinates of either point to solve for b
-1 = (-2)(3/5) + b = -6/5 + b
b = 1/5

Give the equation that is parellel to the following lines and passing through the given points:

(Y-6) = 4(X=3) (-2,7)

ujjy8i

y-6 4x=-24+84

To find the equation of a line that passes through two given points, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this form, m represents the slope of the line, and b represents the y-intercept.

To find the slope (m), we can use the formula:
m = (y2 - y1) / (x2 - x1)

Let's use the given points (-2, -1) and (-7, -4) to calculate the slope (m):

m = (-4 - (-1)) / (-7 - (-2))
m = (-4 + 1) / (-7 + 2)
m = -3 / -5
m = 3/5

Now that we have the slope (m = 3/5), we can substitute it into the slope-intercept form equation along with one of the given points to solve for the y-intercept (b):

Using point (-2, -1):
-1 = (3/5)(-2) + b

Simplifying:
-1 = -6/5 + b

To get b by itself, we need to isolate it by moving -6/5 to the right side of the equation:
b = -1 + 6/5
b = -5/5 + 6/5
b = 1/5

Thus, we have found that the y-intercept (b) is 1/5.

Now we can write the equation of the line using the slope-intercept form (y = mx + b), substituting the values we found:
y = (3/5)x + 1/5