Find an equation of the line containing the give pair of points.
(-2, -1), and (-7, -4). The equation of the line in slope - intercept form is y=
I 've tried this problem and can not seem to get could please help me.
First find the slope, by using y2-y1/x2-x1,and then plug in either one of the ordered pairs into y=mx+b, to find b,the y-intercept. then plug in the slope for m and the y-intercept for b, and youve got it!
Duplicate post; answered elsewhere
if the line is (1,-3) then will the answer be y=-5x+8
To find the equation of the line containing the given pair of points (-2, -1) and (-7, -4), we can use the slope-intercept form of a linear equation, which is:
y = mx + b
Where:
- y represents the y-coordinate of a point on the line
- x represents the x-coordinate of a point on the line
- m represents the slope of the line
- b represents the y-intercept of the line
To calculate the slope (m) using the given points, we can use the formula:
m = (y₂ - y₁) / (x₂ - x₁)
Let's substitute the values of the given points into the slope formula:
m = (-4 - (-1)) / (-7 - (-2))
m = (-4 + 1) / (-7 + 2)
m = -3 / -5
m = 3/5
Now that we have the slope (m), we can proceed to find the y-intercept (b) by substituting the values of one of the points and the slope into the slope-intercept form equation.
Let's use the first point (-2, -1):
-1 = (3/5)(-2) + b [Substituting the values]
-1 = -6/5 + b [Simplifying]
To solve for b, let's move the constant term to the other side of the equation:
b = -1 + 6/5
b = -1 - 6/5
b = -5/5 - 6/5
b = -11/5
Now that we have the slope (m = 3/5) and the y-intercept (b = -11/5), we can write the equation in slope-intercept form:
y = (3/5)x - 11/5
Therefore, the equation of the line in slope-intercept form that contains the points (-2, -1) and (-7, -4) is:
y = (3/5)x - 11/5