AlPO4(s)<=>Al^3+(aq)+PO4^3-(aq)
PO4^3-(aq)+H3O^+(aq)<=>HPO4^2-(aq)+H2O(l)
What is the net ionic equation for AlPO4(s) dissolving in H3O^+(aq)?
Did you throw away the water on the right side? You don't have H2O on the left; therefore, H2O on the right can't be canceled. That could be why your answer isn't accepted.
thanx alot =)
To find the net ionic equation, we need to first write the balanced chemical equation for the reaction of AlPO4 (s) with H3O+ (aq).
The first equation represents the dissociation of AlPO4(s) into Al3+ (aq) and PO43- (aq):
AlPO4(s) <=> Al3+(aq) + PO43-(aq)
The second equation represents the reaction between PO43- (aq) and H3O+ (aq) to form HPO42- (aq) and H2O (l):
PO43-(aq) + H3O+(aq) <=> HPO42-(aq) + H2O(l)
To determine the net ionic equation, we eliminate the spectator ions, which are ions that appear on both sides of the equation unchanged.
The spectator ions in this case are Al3+ and H3O+. They do not participate in any chemical reactions and can be eliminated from the equation.
The net ionic equation for the reaction between AlPO4(s) and H3O+(aq) is:
PO43-(aq) <=> HPO42-(aq) + H2O(l)
Just add the two equations and cancel anything common to both sides of the sum.
i tried dat..n got:
AlPO4(s)+H3O^+(aq)<=>Al^3+(aq)+HPO4^2-(aq)
buh for sum reason its not accepting the answer