A roller coaster begins at the top of a hill. If it accelerates at the rate of 2 m/s^2 and has a mass of 2000 kg, what net force is acting on it? (F=ma)
4000 N
0.001 N
1000 N
If you know the amount of the unbalanced force acting upon an object and the mass of the object, using Newton's 2nd Law what could you calculate about the object?
inertia
acceleration
velocity
A runner accelerates toward the finish line.
Identify the action force in the example.
The wind pushing the runner's face.
The runner's feet pushing against the ground.
The runner pushing against the air.
What is the acceleration of an object with mass of 42.6 kg when an unbalanced force of 112 N is applied to it?
4771.2 m/s^2
0.3800 m/s^2
2.63 m/s^2
A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box?
1.3 N
9.7 N
23.1 N
please help
#1. Use the formula they gave you, ok?
F = ma, so
F = 2000kg * 2m/s^2 = 4000 kg-m/s^2 = 4000N
what do you get on the others?
ok the answers i got are:
2. acceleration
3. runners feet pushing against ground
4. 2.63
5. 23.1 N
can u review these please?
all your answers look good to me.
For the roller coaster question, we can use Newton's second law which states that the force acting on an object is equal to its mass multiplied by its acceleration. In this case, the mass of the roller coaster is 2000 kg and the acceleration is 2 m/s^2. Plugging these values into the formula F = ma, we get F = (2000 kg)(2 m/s^2) = 4000 N. Therefore, the net force acting on the roller coaster is 4000 N.
To calculate different properties of an object using Newton's second law, you need to know either the net force acting on the object or the acceleration of the object in addition to its mass. With this information, you can calculate:
- If you know the force and the mass, you can calculate the acceleration using the formula a = F/m.
- If you know the force and the acceleration, you can calculate the mass using the formula m = F/a.
- If you know the acceleration and the mass, you can calculate the force using the formula F = ma.
In the example of the runner accelerating toward the finish line, the action force is the runner's feet pushing against the ground. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. In this case, the reaction force would be the ground pushing against the runner's feet.
For the next question, we are given the mass of the object (42.6 kg) and the unbalanced force acting upon it (112 N). To calculate acceleration, we can again use Newton's second law: a = F/m. Plugging in the values, we get a = (112 N) / (42.6 kg) ≈ 2.63 m/s^2. Therefore, the acceleration of the object is approximately 2.63 m/s^2.
Finally, for the box being pushed across the lunch table, we are given the mass (5.5 kg) and the acceleration (4.2 m/s^2). Similar to the previous questions, we can use Newton's second law to calculate the net force. Rearranging the formula F = ma, we get F = (5.5 kg)(4.2 m/s^2) ≈ 23.1 N. Therefore, the net force applied to the box is approximately 23.1 N.