if a ping pong ball falls from a top of a building that is 168 feet high, how many seconds will it take the ball to hit the ground? remeber the formula distance is d = 16t^2.
To find out how many seconds it will take for the ping pong ball to hit the ground, we can use the formula for distance and solve for time. The formula is:
d = 16t^2
Where d is the distance and t is the time in seconds.
In this case, the distance is the height of the building, which is 168 feet. So we can rewrite the equation as:
168 = 16t^2
To solve for t, we need to isolate t^2 by dividing both sides of the equation by 16:
168/16 = (16t^2)/16
10.5 = t^2
Now, to solve for t, we need to take the square root of both sides of the equation:
sqrt(10.5) = sqrt(t^2)
3.24 ≈ t
Therefore, it will take approximately 3.24 seconds for the ping pong ball to hit the ground.