Suppose 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2) according to the law of conservation of matter, how many atoms are present in this reaction
C + O2 ==> CO2
10 + 20==> 30 reactants and 30 prducts
30
To determine the number of atoms present in the reaction, we need to consider the atoms involved in the reactants and products.
From the given information, we know that 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
Each molecule of carbon dioxide (CO2) consists of 1 carbon atom and 2 oxygen atoms.
Therefore, the number of carbon atoms in the reactants is 10, and the number of carbon atoms in the products is also 10.
The number of oxygen atoms in the reactants is 20, and the number of oxygen atoms in the products is 10 * 2 = 20.
Thus, in this reaction, there are a total of 10 carbon atoms and 20 oxygen atoms.
To find out how many atoms are present in this reaction, we need to calculate the total number of atoms in the reactants and the total number of atoms in the products.
In the reactants, we have 10 atoms of carbon and 20 atoms of oxygen. To calculate the total number of atoms in the reactants, we simply add these two numbers:
10 atoms of carbon + 20 atoms of oxygen = 30 atoms in the reactants
In the products, we have 10 molecules of carbon dioxide (CO2). Each molecule of carbon dioxide contains 1 atom of carbon and 2 atoms of oxygen. So, to calculate the total number of atoms in the products, we need to multiply the number of molecules of carbon dioxide by the number of atoms in each molecule:
10 molecules of carbon dioxide × (1 atom of carbon + 2 atoms of oxygen) = 10 × (1 + 2) = 10 × 3 = 30 atoms in the products
So, the total number of atoms in this reaction is 30 atoms.