I am a 4 - digit number the digit in the hundreds place is the greatest odd number, and it is 3 times the digit in the hundreds place.The digit in the tens place is twice the digit in the once place.The sum of the day 4 digits is 18.What number am I?

18764

4 digits: xxxx

greatest odd: x9xx
1/3 of that: x93x
Now see whether you can finish it off

The answer you gave is a 5 digit number, not a 4 digit number as asked for.

You also have a typo in "the digit in the hundreds place is the greatest odd number, and it is 3 times the digit in the hundreds place"
mentioning the hundreds place twice

Fix your post

To find the 4-digit number that satisfies the given conditions, we can break down the problem into smaller steps.

Step 1: Find the greatest odd number for the hundreds place.
The greatest odd number is 9 since it is greater than all other odd numbers (1, 3, 5, 7). So the digit in the hundreds place is 9.

Step 2: Determine the multiple of the digit in the hundreds place.
According to the given condition, the digit in the hundreds place is 3 times the digit in the hundreds place. Since the digit in the hundreds place is 9, we can calculate: 9 x 3 = 27.

Step 3: Find the digit in the tens place.
The digit in the tens place is twice the digit in the ones place. Let's assume the digit in the ones place is x. Therefore, the digit in the tens place is 2x.

Step 4: Calculate the sum of the four digits.
We are given that the sum of the four digits is 18. So we can write the equation: 9 + 27 + 2x + x = 18.

Step 5: Solve the equation to find the value of x.
Combining like terms in the equation, we get: 10x + 36 = 18.
Subtracting 36 from both sides of the equation gives: 10x = 18 - 36 or -18.
Dividing both sides of the equation by 10 results in: x = -18/10 or -1.8.

Step 6: Determine the valid range for the ones place.
The ones place digit must be a whole number between 0 and 9. Since x = -1.8 is not within this range, -1.8 cannot be the value of the ones place.

Step 7: Find a valid value for the ones place.
Since -1.8 is not valid, we need to find an integer between 0 and 9. Choosing x = 0, the digit in the ones place is 0.

Step 8: Determine the digit in the tens place.
The digit in the tens place is twice the digit in the ones place. Since the ones place is 0, the tens place digit is also 0.

Step 9: Find the 4-digit number.
Using the information we have gathered, we know that the digits from left to right are 9, 2(0) = 0, 0, and 0. Therefore, the 4-digit number that meets the given conditions is 9000.