Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Mathematics
Given that x varies directly as the square of y and x=2 when y=1, Find x when y=4
1 answer
x = ky^2, so x/y^2 is constant.
You want x such that
x/4^2 = 2/1^2
You can
ask a new question
or
answer this question
.
Related Questions
M varies directly as the square of N. If N increases by 10%, find the percentage change in M
The quantity U is the sum of two terms, one partly constant and the other varies directly as the square of V .if V is 2and U is
A quantity u is the sum of two terms one partly constant and the other varies directly as the square of v if v is 2 when u is 35
p varies directly as q and the square of r and inversely as s
write the equation of the relation find k if p=40 q=5 r=4 s=6 find
A resistance R newtons to the motion of a car varies directly as the square of the speed S.
(A)write the equation conneting R and
given that the energy E,varies directly as the resistance R,as the square of the distance D, obtain an equation connecting E,R
p varies directly as the square of q and inversely as r when p=36, q=3 and r=4 calculate q when p=200 and r=2
a variable y varies directly as the square root of a varies x,and equals 6 when x=4 find y when x=25
when y varies directly at the square of X, the variation equation is written y= kx square, where K is constitution
(a) given that
Y varies directly as the square of x and y=96 when x=4 find the value of y when x=5
