What is the percentage of chlorine ions in a sample if the sample produces 1.0881g of AgCl when treated with excess Ag+
What is the mass of the sample? Call it S.
mass Cl in 1.0881 g AgCl is 1.0881 x (atomic mass Cl/molar mass AgCl) = ?
Then % Cl in sample = (mass Ag/mass Sample)*100 = ?