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If the length of one side of a square is increased by 4 cm and the length of an adjacent side is decreased by 8 cm, the area of the figure is decreased by 20%. Find the length of each side of the square to the nearest tenth.

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2 answers
  1. (s + 4) (s - 8) = (1 - .20) s^2

    s^2 - 4 s - 32 = .8 s^2 ... .2 s^2 - 4 s - 32 = 0 ... s^2 - 20 s - 160 = 0

    use the quadratic formula to find s

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  2. Thanks!

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