A body of mass 58g is suspended at 20cm mark of a uniform rule the meter rule is adjusted on a pivot until it settles horizontally at the40cm mark determine the mass of the meter rule
the 58 g is (40 - 20) or 20 cm from the pivot
the ruler mass m is (50 - 40) or 10 cm from the pivot
so
58 * 20 = m * 10
m = 116 grams
thanks allot
The 58g is (40-20)or 20cm from the pivot the ruler mass is (50-40)or 10cm from the pivot so 50*20=m*10 m=116 grams
To determine the mass of the meter rule, we can use the principle of moments or the balance equation.
In this case, we need to consider the principle of moments. According to this principle, the clockwise moments should be equal to the anticlockwise moments for the meter rule to be in equilibrium.
First, let's find the clockwise moment:
The mass of the body, m = 58 g = 0.058 kg
The distance of the suspended mass from the pivot, d1 = 20 cm = 0.2 m
Clockwise Moment = m * d1
Now, let's find the anticlockwise moment:
The distance of the meter rule's center of mass from the pivot, d2 = 40 cm = 0.4 m
The mass of the meter rule, M kg (which we need to find)
Anticlockwise Moment = M * d2
Since the meter rule is adjusted until it settles horizontally, the clockwise moment must be equal to the anticlockwise moment:
m * d1 = M * d2
Substituting the known values, we have:
0.058 * 0.2 = M * 0.4
Solving for M:
M = (0.058 * 0.2) / 0.4
M = 0.029 kg
Therefore, the mass of the meter rule is 0.029 kg.