I looked for this everywhere, so now you're going to get it.
1) Suppose Ruth Ann has 3 routes she can travel from the school to the library and 5 routes from the library to her home. How many routes are there from Ruth Ann's school to her home with a stop at the library?
Answer - C. 15
2) Verne has 6 math books to line up on a shelf. Jenny has 4 English books to line up on a shelf. In how many more orders can Verne line up his books than Jenny?
Answer - D. 696 (¬‿¬)
3) Evaluate ₇C₆.
Answer - D. 7
4) You have five fruits and you want to choose three of them to combine into a fruit smoothie. In how many ways can three fruits be selected from the five fruits that you have?
Answer - B. 10
5) A bag contains 8 red marbles, 4 white marbles, and 5 blue marbles. You draw one marble at random. Find P(red and blue).
Answer - B. 0
6) A spinner is numbered from 1 through 10 with each number equally likely to occur. What is the probability of obtaining a number less than 2 or greater than 7 in a single spin?
Answer - A. 2/5
7) On the following dartboard, the radius of the bulls-eye (area A) is 4 inches. The radius of each concentric circle is 4 inches more that the circle inside it. If a person throws randomly onto the dartboard, what is the probability that the dart will hit in area B?
Answer - A. 3/16
8) Two urns contain white balls and yellow balls. The first urn contains 9 white balls and 9 yellow balls and the second urn contains 8 white balls and 3 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white?
Answer - A. 4/11
9) If all possible results are equally likely, what is the probability that a spin of the spinner will land on an upper case letter or a consonant?
Answer - A. 0.9
10) Joey's sock drawer is unorganized and contains 3 black dress socks, 5 black ankle socks, 7 brown dress socks, and 6 brown ankle socks. What is the probability that Joey will blindly reach into his sock drawer and pull out a sock that is brown or a dress sock?
Answer - C. 16/21
11) The table shows the results of a survey of students in two math classes. Find P(more than 1 hour of TV | 6th period class). Round to the nearest thousandth.
Did You Watch More Than One Hour of TV Last Night?
ㅤㅤㅤㅤㅤㅤㅤㅤYes No
3rd period classㅤ11ㅤ6
6th period classㅤ13ㅤ10
Answer - B. 0565
12) The probability that a city bus is ready for service when needed is 84%. The probability that a city bus is ready for service and has a working radio is 67%. Find the probability that a bus chosen at random has a working radio given that it is ready for service. Round to the nearest tenth of a percent.
Answer - B. 79.8%
13) A class of 40 students has 11 honor students and 10 athletes. Three of the honor students are also athletes. One student is chosen at random. Find the probability that this student is an athlete if it is known that the student is not an honor student. Round to the nearest thousandth.
Answer - A. 0.241
Good grief this took forever. You're welcome.
Tea is 100% correct, idk what mathhelper is talking bout
Tea is 100% right
tea is right just took it and all was right
TEA YOU ARE THE REALEST TY
Tea got me 100%! Thank you!
1) To find the number of routes from Ruth Ann's school to her home with a stop at the library, we multiply the number of routes from the school to the library (3) by the number of routes from the library to her home (5). 3 x 5 = 15. Therefore, the answer is 15 routes.
2) To find the number of more orders Verne can line up his books compared to Jenny, we subtract the number of orders Jenny can line up her books from the number of orders Verne can line up his books. Verne has 6! (6 factorial) = 6 x 5 x 4 x 3 x 2 x 1 = 720 possible orders. Jenny has 4! (4 factorial) = 4 x 3 x 2 x 1 = 24 possible orders. Therefore, Verne can line up his books in 720 - 24 = 696 more orders than Jenny.
3) To evaluate ₇C₆ (7 choose 6), we use the formula for combinations: nCr = n! / (r!(n-r)!). Plugging in the values, ₇C₆ = 7! / (6!(7-6)!) = 7! / (6!1!) = 7 / 1 = 7. Therefore, the answer is 7.
4) To find the number of ways three fruits can be selected from the five fruits you have, we use the formula for combinations. 5C3 = 5! / (3!(5-3)!) = 5! / (3!2!) = (5 x 4 x 3!) / (3! x 2!) = (5 x 4) / 2 = 10. Therefore, there are 10 ways to select three fruits from the five fruits available.
5) To find the probability of drawing a red and blue marble, we need to calculate the probability of drawing a red marble and a blue marble separately, and then multiply those probabilities together. The probability of drawing a red marble is 8 red marbles / (8 + 4 + 5) total marbles = 8/17. The probability of drawing a blue marble is 5 blue marbles / (8 + 4 + 5) total marbles = 5/17. Multiplying these probabilities together, we get (8/17) x (5/17) = 40/289. Therefore, the probability of drawing a red and blue marble is 40/289.
6) To find the probability of obtaining a number less than 2 or greater than 7 in a single spin of the spinner, we need to calculate the probability of each event separately and then add them together. The probability of getting a number less than 2 is 1/10, and the probability of getting a number greater than 7 is 3/10 (since there are three numbers greater than 7: 8, 9, and 10). Adding these probabilities together, we get 1/10 + 3/10 = 4/10 = 2/5. Therefore, the probability of obtaining a number less than 2 or greater than 7 in a single spin is 2/5.
7) To find the probability that the dart will hit in area B, we need to calculate the ratio of the area of B to the total area of the dartboard. The area of B is (π(8^2) - π(4^2)) = (π(64) - π(16)) = 48π. The total area of the dartboard is π(12^2) = π(144) = 144π. Therefore, the probability is 48π/144π = 48/144 = 1/3. Simplifying, the probability is 1/3. Therefore, the answer is 1/3.
8) To find the probability that both balls drawn are white, we need to calculate the probability of drawing a white ball from the first urn and a white ball from the second urn, and then multiply those probabilities together. The probability of drawing a white ball from the first urn is 9 white balls / (9 + 9) total balls = 9/18 = 1/2. The probability of drawing a white ball from the second urn is 8 white balls / (8 + 3) total balls = 8/11. Multiplying these probabilities together, we get (1/2) x (8/11) = 4/11. Therefore, the probability of both balls being white is 4/11.
9) To find the probability of landing on an uppercase letter or a consonant, we need to calculate the probability of landing on an uppercase letter and the probability of landing on a consonant, and then subtract the probability of landing on both an uppercase letter and a consonant (to avoid double counting). The probability of landing on an uppercase letter is 26 uppercase letters / 26 total letters = 1. The probability of landing on a consonant is 21 consonants / 26 total letters = 21/26. The probability of landing on both an uppercase letter and a consonant is the same as the probability of landing on a consonant, which is 21/26. Therefore, the probability of landing on an uppercase letter or a consonant is 1 + 21/26 - 21/26 = 1. Therefore, the answer is 1.
10) To find the probability of pulling out a brown sock or a dress sock blindly from Joey's sock drawer, we need to calculate the ratio of the number of favorable outcomes (brown socks or dress socks) to the number of possible outcomes (all socks). The number of brown socks is 7, and the number of dress socks is 3. The total number of socks is 3 + 5 + 7 + 6 = 21. Therefore, the probability is (7 + 3) / 21 = 10 / 21. Simplifying, the probability is 10/21. Therefore, the answer is 10/21.
11) To find the probability of watching more than 1 hour of TV given that the class is the 6th period class, we divide the number of students in the 6th period class who watched more than 1 hour of TV (13) by the total number of students in the 6th period class (13 + 10 = 23). Therefore, the probability is 13/23.
12) To find the probability of a bus having a working radio given that it is ready for service, we divide the probability of a bus being ready for service and having a working radio (67%) by the probability of a bus being ready for service (84%). Therefore, the probability is (67/84) x 100 = 79.8%.
13) To find the probability of selecting an athlete given that the student is not an honor student, we divide the number of athletes who are not honor students (10 - 3 = 7) by the number of students who are not honor students (40 - 11 = 29). Therefore, the probability is 7/29.
I checked the first 10 and found
#s 1, 2, 3, 4, 5, 6, 8, 10 correct
#9, we don't really know what the spinner looks like.
e.g. Are there 26 upper and 26 lower letters?
#7, How many rings does your board have, this doesn't look a
standard dartboard.