The number of hours a group of contestants spends preparing for a quiz show is listed below. What is the frequency table that represents that data?

8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
------------------------------------
Option 1.
Hours. Frequency
-------------------------------------
0-9. 3
10-19. 2
20-29. 1
30-39. 4
40-49. 1
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 1
---------------------------------
Option 2.
Hours. Frequency
-------------------------------------
0-9. 2
10-19. 3
20-29. 1
30-39. 3
40-49. 2
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 1
-----------------------------------------
Option 3.
Hours. Frequency
---------------------------------------
0-9. 4
10-19. 1
20-29. 0
30-39. 4
40-49. 2
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 1
--------------------------------------
Option 4.
Hours. Frequency
----------------------------------------
0-9. 3
10-19. 2
20-29. 1
30-39. 4
40-49. 1
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 2
------------------------------------
My answer is option #4

8 4 and 9 is 3 from 0 to 9

so has to be 1 or 4

option 1 has 1 from 90 to 99
but there are 2 in option 4

so I think option 1

So was it option 1? Or option 4

22. What are the minimum, first quartile, median, third quartile, and maximum of the data set?

18, 20, 11, 10, 8, 6, 12, 4 (1 point)
minimum 4; first quartile 7; median 10.5; third quartile 17.5; maximum 20
minimum 4; first quartile 5.5; median 12.75; third quartile 15; maximum 20
minimum 4; first quartile 8.75; median 12.75; third quartile 17.5; maximum 20
minimum 4; first quartile 7; median 10.5; third quartile 15; maximum 20
23. Simplify –(3ab2)–3 (1 point)
(Image: 1 over 9a3b6)
(Image: –1 over 27a3b6)
(Image: –1 over 3a3b5)
27a3b6

23. Simplify –(3ab2)–3:

-(3ab^2)^-3

= -1/(3ab^2)^3

= -1/(27a^3b^6)

The answer is (Image: –1 over 27a3b6).

To create a frequency table for the given data, you need to count the number of times each range of hours appears in the data set.

Here is how you can calculate the frequencies for each option:

Option 1:
- 0-9: Count 4 (8, 4, 9, 4)
- 10-19: Count 2 (12, 18)
- 20-29: Count 0
- 30-39: Count 4 (32, 36, 33, 39)
- 40-49: Count 1 (45)
- 50-59: Count 1 (50)
- 60-69: Count 2 (62, 67)
- 70-79: Count 1 (73)
- 80-89: Count 1 (80)
- 90-99: Count 1 (99)

Option 2:
- 0-9: Count 2 (4, 8)
- 10-19: Count 3 (12, 18, 9)
- 20-29: Count 0
- 30-39: Count 3 (32, 36, 33)
- 40-49: Count 2 (45, 39)
- 50-59: Count 1 (50)
- 60-69: Count 2 (62, 67)
- 70-79: Count 1 (73)
- 80-89: Count 1 (80)
- 90-99: Count 1 (99)

Option 3:
- 0-9: Count 4 (8, 4, 9, 4)
- 10-19: Count 1 (12)
- 20-29: Count 0
- 30-39: Count 4 (32, 36, 33, 39)
- 40-49: Count 2 (45, 39)
- 50-59: Count 1 (50)
- 60-69: Count 2 (62, 67)
- 70-79: Count 1 (73)
- 80-89: Count 1 (80)
- 90-99: Count 1 (99)

Option 4:
- 0-9: Count 3 (8, 4, 9)
- 10-19: Count 2 (12, 18)
- 20-29: Count 1 (25)
- 30-39: Count 4 (32, 36, 33, 39)
- 40-49: Count 1 (45)
- 50-59: Count 1 (50)
- 60-69: Count 2 (62, 67)
- 70-79: Count 1 (73)
- 80-89: Count 1 (80)
- 90-99: Count 2 (99, 36)

Comparing the calculated frequencies to the options, it looks like option 4 matches the given data. So, your answer, option 4, is correct.