algebra 1 help!! 8th grade NON HONORS CONNEXUS
Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
the ordered pair (2, negative 2) ;y equals negative x minus 2.
A. y equals negative 2 x.
B. y equals 2 x.
C. y equals one-half x.
D. y equals negative x.
nevermind
here are the answers :)) (pearson 6.6.5 practice)
y=-x (D)
y=3/2x+2(C)
x=4 (D)
y=-2x-1 (B)
y=-1/2x+5/2 (D)
Perp (B)
Parallel (A)
Neither (C)
Sometimes (B)
never (C)
i genuinely don't understand how to do these problems.
To write an equation in slope-intercept form of a line parallel to a given equation, we need to find the slope of the given equation.
The given equation is y = -x - 2. The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
In the given equation, the coefficient of x is -1, which is the slope. So, the slope of the given equation is -1.
Since the line we are looking for is parallel to the given equation, it will have the same slope. Now, we can use the slope-intercept form of the line and the given point (2, -2) to find the equation.
Substituting the point (2, -2) and the slope (-1) into the slope-intercept form, we have:
y = mx + b
-2 = -1(2) + b
Simplifying:
-2 = -2 + b
b = 0
Therefore, the equation in slope-intercept form of the line that passes through the point (2, -2) and is parallel to the given equation is:
y = -x + 0
Simplifying further:
y = -x
So, the correct answer is D. y = -x.