a golf ball was hit and projeted at an angle of 50 degree with respect to the horizontal the ball had an initial velocity of 60m/s.

Is there a question here?

What is the total time the golf ball was in the air?

A. 4.69 s B. 7.69 s C. 8.38 s D. 9.38 s
What is the horizontal displacement of the golf ball?
A. 341.79 m B. 351.79m C. 361.79 m D. 371.79 m
How far did the golf ball reach?
A. 105.77 m B. 107.77 m C. 109.77 m D. 109.87 m

To find out the horizontal and vertical components of the initial velocity, we can use trigonometry. The horizontal component (Vx) can be found using the formula Vx = V * cos(angle), and the vertical component (Vy) can be found using Vy = V * sin(angle).

Given:
Initial velocity (V) = 60 m/s
Angle (angle) = 50 degrees

To find Vx:
Vx = V * cos(angle)
Vx = 60 * cos(50)
Vx ≈ 60 * 0.6428
Vx ≈ 38.568 m/s

To find Vy:
Vy = V * sin(angle)
Vy = 60 * sin(50)
Vy ≈ 60 * 0.7660
Vy ≈ 45.960 m/s

So, the horizontal component of the initial velocity is approximately 38.568 m/s, and the vertical component is approximately 45.960 m/s.