what is the percentage by mass of sulphur in aluminium tetraoxosulphate(VI), Al2(SO4)3
By the way, aluminium tetraoxosulphate(VI) is not an approved IUPAC name for Al2(SO4)3 but aluminium sulphate is.
molar mass = mm = 2*Al + 3*96 = ?
mass S in Al2(SO4)3 is 1 mol S or 32 g S per mol Al2(SO4)3.
%S = [32/mm Al2(SO4)3]*100 = ?
Oh, sulfur is trying to make an impact here, huh? Alright, let's figure this out. Now, our trusty friend Aluminium Tetraoxosulphate(VI), or Al2(SO4)3, contains a total of 3 sulfur atoms (indicated by the subscript 3), and a single molecule of Al2(SO4)3 weighs approximately 342 grams.
To calculate the percentage by mass of sulfur, we need to determine the molar mass of sulfur and divide it by the molar mass of the entire compound. The atomic mass of sulfur is approximately 32.06 g/mol.
So, the molar mass of Al2(SO4)3 is:
2(atomic mass of Al) + 3(atomic mass of S) + 12(atomic mass of O) x 4
Now, let's plug in the numbers:
2(26.98) + 3(32.06) + 12(16.00) x 4 = 342.12g/mol
Now, let's calculate the percentage by mass of sulfur:
(mass of sulfur / total molar mass) x 100
(3)(32.06) / 342.12 x 100 ≈ 28.19%
So, approximately 28.19% of the mass of Aluminium Tetraoxosulphate(VI) is sulfur. That's a sulfur-ceful outcome if you ask me!
To find the percentage by mass of sulfur in aluminum tetraoxosulfate(VI) (Al2(SO4)3), we need to calculate the molar mass of sulfur and the molar mass of the compound.
The molar mass of sulfur (S) is 32.06 g/mol.
The molar mass of aluminum tetraoxosulfate(VI) (Al2(SO4)3) can be calculated as follows:
- The atomic mass of aluminum (Al) is 26.98 g/mol.
- The atomic mass of sulfur (S) is 32.06 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
The molar mass of Al2(SO4)3 can be calculated as:
2 * (26.98 g/mol Al) + 3 * (32.06 g/mol S) + 12 * (16.00 g/mol O)
= 53.96 g/mol Al + 96.18 g/mol S + 192.00 g/mol O
= 342.14 g/mol
Now, we can calculate the percentage by mass of sulfur in Al2(SO4)3 using the following formula:
Percentage by mass = (Molar mass of sulfur / Molar mass of Al2(SO4)3) * 100
Percentage by mass = (96.18 g/mol / 342.14 g/mol) * 100
≈ 28.15%
Therefore, the percentage by mass of sulfur in aluminum tetraoxosulfate(VI), Al2(SO4)3, is approximately 28.15%.
To calculate the percentage by mass of sulfur in aluminum tetraoxosulfate (VI), Al2(SO4)3, we need to determine the molar mass of sulfur and the molar mass of the entire compound.
First, let's calculate the molar mass of sulfur (S). Sulfur has an atomic mass of approximately 32.06 g/mol.
Next, let's calculate the molar mass of the entire compound, Al2(SO4)3.
- Aluminum (Al) has an atomic mass of approximately 26.98 g/mol, and since we have two aluminum atoms, the contribution from aluminum is 2 * 26.98 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol, and since we have three sulfate (SO4) groups containing four oxygen atoms each, the contribution from oxygen is 3 * 4 * 16.00 g/mol.
- Since we have three sulfate (SO4) groups, we also need to consider the contribution from sulfur (S), which is 3 * 32.06 g/mol.
Now, add up the contributions from all the elements:
- Contribution from aluminum: 2 * 26.98 g/mol = 53.96 g/mol
- Contribution from oxygen: 3 * 4 * 16.00 g/mol = 192 g/mol
- Contribution from sulfur: 3 * 32.06 g/mol = 96.18 g/mol
The molar mass of Al2(SO4)3 is 53.96 g/mol + 192 g/mol + 96.18 g/mol = 342.14 g/mol.
To determine the percentage by mass of sulfur, divide the molar mass of sulfur by the molar mass of the entire compound and multiply by 100:
Mass percentage of sulfur = (Mass of sulfur / Mass of compound) x 100
Mass percentage of sulfur = (96.18 g/mol / 342.14 g/mol) x 100 ≈ 28.16%
Therefore, the percentage by mass of sulfur in aluminum tetraoxosulfate(VI), Al2(SO4)3, is approximately 28.16%.