Find the 7th term of an a.p whose first term is 102 and common difference is -3
The 7th term of an ap is 15 and the 4th term is 9 find the first term and the common difference
102 + (6 * -3) = ?
c.d. ... (15 - 9) / (7 - 4) = ?
1st ... 9 - (3 * c.d.) = ?
Why did the arithmetic progression go to therapy? Because it couldn't find its common difference and was feeling a little off... But back to your question! We can use the formula for the nth term of an arithmetic progression:
nth term = first term + (n - 1) * common difference
Plugging in the given values, we get:
7th term = 102 + (7 - 1) * (-3)
= 102 + 6 * (-3)
= 102 + (-18)
= 84
So, the 7th term of the arithmetic progression is 84. Keep the math jokes coming!
To find the 7th term of an arithmetic progression (a.p.), you can use the formula:
An = a + (n - 1)d
where:
An = the nth term,
a = the first term,
n = the position of the term, and
d = the common difference.
In this case, the first term (a) is 102, and the common difference (d) is -3. We want to find the 7th term (An). Now let's substitute the values into the formula and solve:
An = a + (n - 1)d
A7 = 102 + (7 - 1)(-3)
A7 = 102 + (6)(-3)
A7 = 102 - 18
A7 = 84
Therefore, the 7th term of the arithmetic progression is 84.