A ball is thrown into the air with an initial upward velocity of 48ft/s its height h in feet after t seconds is given by the function h = 16t^2 + 48t + 64
6 seconds
4 seconds
7 seconds
5 seconds
3 answers

all or any of the above, depending on the question ...

Sorry, I forgot to put part of the question.
A ball is thrown into the air with an initial upward velocity of 48ft/s its height h in feet after t seconds is given by the function h=16t^2 + 48t + 64 After how many seconds will the ball hit the ground?

when it hits the ground, the height is zero, right?
so just solve
16t^2 + 48t + 64 = 0
or, dividing by 16,
t^2  3t  4 = 0
sure looks like t=4
