A football player kicked a football with an initial velocity of 30 m/s. at an angle 60°
did the ball pop?
initial vertical speed = Vi = 30 sin 60 = 26 m/s
v = Vi - 9.81 t , if on earth
v = 0 at top (halfway through trip)
t = 26 / 9.81 = 2.65 seconds upward, total 5.3 aloft
max height = Vi t - 4.9 t^2 = 34.5
range = 30 cos 60 * 5.3 = 15*5.3 = 75.5 meters
To determine the horizontal and vertical components of the initial velocity, we can use trigonometry.
The horizontal component of the initial velocity (Vx) can be found using the cosine of the angle:
Vx = 30 m/s * cos(60°)
Vx = 30 m/s * 0.5
Vx = 15 m/s
The vertical component of the initial velocity (Vy) can be determined using the sine of the angle:
Vy = 30 m/s * sin(60°)
Vy = 30 m/s * 0.866
Vy ≈ 25.98 m/s
Therefore, the horizontal component of the initial velocity is 15 m/s, and the vertical component is approximately 25.98 m/s.