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In a box containing 11 red balls, 12 green balls and 5 yellow balls. Two balls are drawn one by one without replacement, what is the probability that

(correct your answers to 4 decimal places.)
both of them are the same color?
both of them are not green?

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2 answers
  1. most likely red since there is more red

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  2. really? last I checked, 12 > 11

    the first ball can be any color. then there are 27 balls left
    P(red,red) = 10/27
    P(green,green) = 11/27
    P(yellow,yellow) = 4/27
    So P(same color) = 25/27

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