Write the equation of the line parallel to y = 3x + 4 passing through (0, 9).
you have a point and a slope, so
y-9 = 3(x-0)
or
y = 3x+9
To find the equation of a line parallel to y = 3x + 4, we know that parallel lines have the same slope. The slope of the given line is 3.
Using the point-slope form of a linear equation, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line, we can substitute the values (0, 9) to find the equation of the desired line.
Thus, the equation of the line parallel to y = 3x + 4 passing through (0, 9) is:
y - 9 = 3(x - 0)
y - 9 = 3x
The final equation of the line is y = 3x + 9.
To find the equation of a line parallel to another line, we can use the fact that parallel lines have the same slope. In this case, the original line has a slope of 3.
We also know that the line we are looking for passes through the point (0, 9). To find the equation, we can use the point-slope form of the equation of a line, which is:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Let's substitute the values into the formula:
y - 9 = 3(x - 0)
Simplifying:
y - 9 = 3x
Now, we can rewrite the equation in slope-intercept form:
y = 3x + 9
So, the equation of the line parallel to y = 3x + 4 passing through (0, 9) is y = 3x + 9.