A cross-country competitor runs on a bearing of north 60 degrees west for 2 km, then due north for 3 km. a. How far is he from the starting point? b. What is the true bearing of the starting point from the runner?

(a) d^2 = 2^2 + 3^2 - 2*2*3*cos120°

(b) The runner ends up 1km west and 3+√3 km north of the starting point.
so the bearing to the starting point is 90+θ, where
tanθ = 3+√3