The perimeter of a Rectangular pool is 280 yards. If the length is 40 yards less than twice the width, find the length and width.
width --- x
length = 2x - 40
2(x + 2x-40) = 280
solve for that mysterious x , then sub into my definitions
Im at school im outside rn lol
To find the length and width of the rectangular pool, we need to set up a system of equations based on the given information.
Let's represent the width of the pool as 'w' yards and the length as 'l' yards.
Based on the given information, we have:
1) The perimeter of the rectangular pool is 280 yards:
Perimeter = 2(length + width)
280 = 2(l + w)
2) The length is 40 yards less than twice the width:
l = 2w - 40
Now, we can solve these equations simultaneously to find the values of 'l' and 'w'.
Substituting equation 2 into equation 1, we have:
280 = 2((2w - 40) + w)
Simplifying the equation, we get:
280 = 2(3w - 40)
140 = 3w - 40
180 = 3w
w = 60
Substituting the value of w back into equation 2 to find l:
l = 2w - 40
l = 2(60) - 40
l = 120 - 40
l = 80
Therefore, the width of the rectangular pool is 60 yards and the length is 80 yards.
2(w + 2w-40) = 280
3w-40 = 140
3w = 180
w = 60
so the length is 2*60-40 = 80
check: 2(60+80) = 280 ✅