how many moles of Al2O3 will be formed when 27grams of Al reacts completely with O2? (1) 1.0 (2)2.0 (3)0.50 (4)4.0 pls show the work

0.5

To determine the number of moles of Al2O3 formed when 27 grams of Al reacts completely with O2, we need to use the balanced chemical equation for the reaction.

The balanced equation for the reaction between Al and O2 to form Al2O3 is as follows:

4 Al + 3 O2 → 2 Al2O3

To calculate the number of moles of Al2O3 formed, we can follow these steps:

Step 1: Convert the given mass of Al (27 grams) to moles.
Molar mass of Al = 27 g/mol. Therefore, the number of moles of Al can be calculated as:
Number of moles of Al = Mass of Al / Molar mass of Al
= 27 g / 27 g/mol
= 1 mole

Step 2: According to the balanced chemical equation, the reaction ratio between Al and Al2O3 is 4:2. This means that for every 4 moles of Al, 2 moles of Al2O3 are formed.

Step 3: Apply the reaction ratio to calculate the moles of Al2O3 formed.
Number of moles of Al2O3 = (Number of moles of Al / Ratio of Al to Al2O3) x Ratio of Al2O3 to Al
= (1 mole / 4) x 2
= 0.5 moles

Therefore, 0.5 moles of Al2O3 will be formed when 27 grams of Al reacts completely with O2.

Hence, the correct answer is (3) 0.50.

To determine the number of moles of Al2O3 formed when 27 grams of Al reacts completely with O2, we need to use the balanced chemical equation for the reaction.

The balanced equation for the reaction is:
4Al + 3O2 -> 2Al2O3

We can use the concept of molar ratios to convert the given mass of Al to the number of moles of Al2O3 formed.

Step 1: Calculate the molar mass of Aluminum (Al)
The molar mass of Al is 26.98 g/mol.

Step 2: Calculate the number of moles of Al using its molar mass and the given mass.
Number of moles = Mass / Molar mass
Number of moles of Al = 27 g / 26.98 g/mol = 1.000 mol (approx.)

Step 3: Use the molar ratio from the balanced equation to find the number of moles of Al2O3 formed.
From the balanced equation, we know that 4 moles of Al react to form 2 moles of Al2O3.
Therefore, the molar ratio of Al2O3 to Al is 2/4 = 0.5 (1 mol Al2O3 : 2 mol Al)

Step 4: Multiply the number of moles of Al by the molar ratio of Al2O3 to Al to find the number of moles of Al2O3 formed.
Number of moles of Al2O3 = Number of moles of Al * Molar ratio of Al2O3 to Al
Number of moles of Al2O3 = 1.000 mol * 0.5 = 0.500 (approx.)

Therefore, the answer is 0.50 moles of Al2O3 formed when 27 grams of Al reacts completely with O2.

So, the correct option is (3) 0.50.

how many moles of Al in 27g?

The equation will tell you how many moles of Al2O3 you will get.