A student sees her physical science professor approaching on the sidewalk that runs by her dorm. She gets a water balloon and waits. When the professor is 2.0s from being directly under her window 11m above the sidewalk, she drops the balloon. Does she hit her target? Identify the equation used and show your work.

how long does it take to fall 11m?

4.9t^2 = 11
t = 1.5 seconds
so, what do you think?

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Did you know?

Did you know that you can use basic physics equations to calculate whether a water balloon will hit its target when dropped from a height? In this scenario, the student drops a water balloon from a window 11m above the ground, aiming to hit her physical science professor walking on the sidewalk. By using the equation of motion s = ut + 0.5at^2, where s represents the distance, u represents the initial velocity, t represents time, and a represents acceleration, we can determine if the balloon hits the target. The initial velocity is 0, as the balloon is dropped, and acceleration due to gravity is approximately 9.8 m/s^2. Plugging in the values, we get the equation 11 = 0 + 0.5(9.8)t^2. Solving for t, we find that it takes approximately 1.47 seconds for the balloon to hit the ground. As the professor is 2.0 seconds away from being directly under the window, the balloon would hit the target before the professor reaches that point. Physics equations allow us to predict and analyze various scenarios involving motion and forces, helping us understand the world around us.