Three cells, each with an EMF of 2,5V and an internal resistance of 0,2 ohms are connected in series and across a 1,5 V resistor
Calculate the current flowing through the current
1,5 V resistor
What ? Please proofread.
15 Ohms resistor.
Not 1.5V resistor 😑
ok
in series so total R = 0.6 + 15 = 15.6 ohms
V = 3 * 2.5 = 7.5
i = V/R = 7.5 / 15.6 = 0.481 amps
Okay
* Got it ✌
To calculate the current flowing through the circuit, we first need to determine the total EMF and total internal resistance of the system.
Since the three cells are connected in series, the total EMF will be the sum of the individual EMFs:
Total EMF = 3 * EMF of each cell = 3 * 2.5V = 7.5V
Similarly, the total internal resistance will be the sum of the individual internal resistances:
Total internal resistance = 3 * internal resistance of each cell = 3 * 0.2Ω = 0.6Ω
Now, we can use Ohm's Law to find the current flowing through the circuit. Ohm's Law states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R):
I = V / R
In this case, the voltage across the resistor is 1.5V and the resistance is given. Plugging in these values:
I = 1.5V / 1.5Ω = 1A
Therefore, the current flowing through the circuit is 1A.