There are a total of 198 coins in a bag, all of which are nickels, dimes, and quarters.

The number of nickels is four times the number of quarters.
There are twice as many quarters as there are dimes.
If the total amount of money is \$18.00, how many nickels, dimes, and quarters are in the bag?
There are nickels, dimes, and quarters.
I am not sure how to do this, can someone please explain?

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1. just write the data in math
n+d+q = 198
n = 4q
q = 2d
That is enough to find how many of each coin there are.
The amount doesn't really matter, but its equation is
5n+10d+25q = 1800

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2. hey oobleck, thanks for trying but, the correct way to solve it was different than what you advised... the correct way was..
let x=#of dimes; let 2x=#of quarters; and let 8x=#of nickels. That makes x+2x+8x=198 which then x=18. Therefore there was 18 dimes; 36 quarters; and 144 nickels. thanks for trying.

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3. sure - you will note that if you use my equations, you will get
q = 2d and n = 8d
x,y,z will also work, of course.

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