NEED HELP WITH THESE TWO

1. Find the critical values x2l and x2r that correspond to a 95% confidence level and a sample size of 9.
A. 2.733, 15.507
B. 1.344, 21.955
C. 2.180, 17.535
D. 2.700, 19.023

2. 61 random samples of city rent prices are selected from a normally distributed population. the samples have a mean of $738 and a standard deviation of $41. Construct a 95% confidence interval for the population standard deviation.
A. $34.80 < a<$49.91
B. $5.50 <a< $7.90
C. $32.80 <a <$45.91
D. $38.20 <a <$47.20

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1.) 2.180, 17.535

2.) $34.80 < o < $49.91

To solve these two questions, we need to understand the concepts of critical values and confidence intervals.

1. Find the critical values x2l and x2r that correspond to a 95% confidence level and a sample size of 9.

To find the critical values for this scenario, we need to refer to the chi-square distribution table. The critical values of the chi-square distribution depend on the desired confidence level and the sample size.

For a 95% confidence level and a sample size of 9, we will use a two-tailed test. The chi-square distribution is symmetric, so the critical values on both sides of the distribution will be equal in magnitude.

Looking at the chi-square distribution table with 8 degrees of freedom (sample size minus 1), we need to find the closest values to 95% confidence level. From the options provided, the critical values that correspond to a 95% confidence level are:
A. 2.733, 15.507.

Therefore, the answer is A. 2.733, 15.507.

2. 61 random samples of city rent prices are selected from a normally distributed population. The samples have a mean of $738 and a standard deviation of $41. Construct a 95% confidence interval for the population standard deviation.

To construct a confidence interval for the population standard deviation, we will use the chi-square distribution with the chi-square formula for population standard deviation.

For a 95% confidence interval, we will use the values associated with a 2.5% probability in each tail of the distribution, because we want a two-tailed test. Degrees of freedom for this scenario is equal to the sample size minus 1, which is 61 - 1 = 60.

To find the critical values for the chi-square distribution in each tail, we can use the chi-square distribution table. The 2.5% probability in each tail corresponds to 0.025 in the table.

From the given options, the 95% confidence interval for the population standard deviation is:
C. $32.80 < a < $45.91.

Therefore, the answer is C. $32.80 < a < $45.91.

This is cheating and wont help you at all. Reach out to your teacher if you need help. They will help you this WONT!!