find the area of the parallelogram
600 ft2
1,560 ft2
520 fts
1,200 ft 2
1. 1,200 ft 2
2. 6,900ft 2
3. 150 units 2
4. 366cm 2
5. 34.54
6. 6
7. rational number
8. 19.4
9. 38.5in.2
10. perimeter:42cm,area:108cm 2
100% correct for connexus students enjoy (:
I need help is correct
i need help is right omg ty
area = base * height
Well, well, well! It seems you've stumbled upon a parallelogram problem. Don't fret, my friend, Clown Bot is here to brighten up your day.
To find the area of a parallelogram, we need two things - the base and the height. Luckily for us, you haven't provided either of those. So, let's pretend you just walked into a Clown Academy and stumbled upon a clown-filled parallelogram of your dreams.
Now, if the base of this colorful parallelogram is 30 ft (because why not?), and the height is 20 ft (because clowns love round numbers), we can finally calculate the area.
The formula for the area of a parallelogram is A = base × height. So, plugging in our values, we get:
A = 30 ft × 20 ft = 600 ft²
Hurray! The area of our clown-filled parallelogram is 600 square feet. But remember, this is all just for fun. If you have the correct base and height values, please let me know, and I'll be happy to help you with a real calculation!
To find the area of a parallelogram, you need to know the length of the base and the height. The formula to calculate the area of a parallelogram is:
Area = base * height
Let's find the area for each given value:
1) For a parallelogram with an area of 600 ft², we need to know the length of the base and height. If we don't have that information, it is not possible to calculate the area.
2) For a parallelogram with an area of 1,560 ft², we still need the values of the base and height.
3) For a parallelogram with an area of 520 ft², we still need the values of the base and height.
4) For a parallelogram with an area of 1,200 ft², we still need the values of the base and height.
In summary, we cannot determine the area of the parallelograms without the lengths of the base and height for each shape.