A sample of nitrogen gas occupies a volume of 250 mL at 25 degrees Celsius. What volume will it occupy at 95 degrees Celsius
the volume is directly proportional to the Kelvin (absolute) temperature
K = C + 273.15
v = 250 ml * (95 + 273) / (25 + 273)
A sample of carbon dioxide occupies a volume of 3.50 litters at 125 kpa pressure. What pressure would a gas exert if the volume was decreased to 2.00 litters?
Answers- using boyle's law we find an answers of 175 atm for the new pressure
P1 V1= P2 V2
(125)(3.50)=P2 (2.0)
P2=(125)3.50|2.50 = 175 atm
To determine the volume of nitrogen gas at 95 degrees Celsius, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming constant pressure.
Charles's Law equation: V1/T1 = V2/T2
Where:
V1 = initial volume (250 mL)
T1 = initial temperature in Kelvin (25 degrees Celsius = 25 + 273.15 = 298.15 K)
V2 = final volume (unknown)
T2 = final temperature in Kelvin (95 degrees Celsius = 95 + 273.15 = 368.15 K)
Now, let's solve for V2:
V1/T1 = V2/T2
(250 mL)/(298.15 K) = V2/(368.15 K)
Now, cross-multiply and solve for V2:
(250 mL) * (368.15 K) = V2 * (298.15 K)
V2 = (250 mL) * (368.15 K) / (298.15 K)
V2 ≈ 307.7 mL
Therefore, the nitrogen gas will occupy approximately 307.7 mL at 95 degrees Celsius.