A 6kg mass is resting on a horizontal surface. it is determined that a force of 20N will start the object sliding and keep it sliding with an acceleration of 0.83. what are the coefficient of static friction and kinetic friction between the mass and the surface?

First the static friction

F = mu m g
20 = mu * 6 * 9.81 (on earth)
mu = 20 / (6*9.81) = 0.34 static
then sliding
F - mu m g = m a
20 - mu (6*9.81) = 6 *0.83
58.9 mu = 20 - 4.98 = 15
mu = 0.25 kinetic

I need the answer now

Sorry to be so slow about the reply. I retired long before you were born I suspect (was a student at Punahoe school when Pearl Harbor was bombed) and have trouble keeping up.

Really appreciate to the answer thank u guys help a lot

To determine the coefficient of static friction (μs) and kinetic friction (μk) between the mass and the surface, we can use the equation:

Force of friction (Ff) = coefficient of friction (μ) × normal force (N)

First, let's calculate the normal force acting on the mass:

Normal force (N) = mass (m) × gravitational acceleration (g)
= 6 kg × 9.8 m/s²
= 58.8 N

Now, let's find the coefficient of static friction (μs):

For the object to start sliding, the force of friction must equal the force applied:

Ff = μs × N
20 N = μs × 58.8 N

Solving for μs:
μs = 20 N / 58.8 N
μs ≈ 0.34

Therefore, the coefficient of static friction (μs) between the mass and the surface is approximately 0.34.

Next, let's determine the coefficient of kinetic friction (μk):

Since the object is already sliding, the force of friction is given by:

Force of friction (Ff) = μk × N
Ff = 20 N (as given)

So, we can now solve for μk:
20 N = μk × 58.8 N

Solving for μk:
μk = 20 N / 58.8 N
μk ≈ 0.34

Therefore, the coefficient of kinetic friction (μk) between the mass and the surface is approximately 0.34.

The coefficient of static friction and kinetic friction between the mass and the surface is 0.34.