Calculate the mass of hydrochloric acid needed to react with 5.00 moles of zinc in a single replacement reaction.

To calculate the mass of hydrochloric acid needed to react with 5.00 moles of zinc, we need to determine the balanced chemical equation for the reaction between zinc and hydrochloric acid.

The balanced chemical equation for this reaction is:
Zn + 2HCl → ZnCl2 + H2

From the equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride and 1 mole of hydrogen gas.

Since we have 5.00 moles of zinc, we can use stoichiometry to find the corresponding amount of hydrochloric acid needed.

Using the ratio from the balanced equation, we know that:
1 mole of zinc reacts with 2 moles of hydrochloric acid

Therefore, 5.00 moles of zinc will react with:
5.00 moles zinc × (2 moles hydrochloric acid / 1 mole zinc) = 10.00 moles of hydrochloric acid

Now, to find the mass of hydrochloric acid, we need to use its molar mass. The molar mass of hydrochloric acid (HCl) is the sum of the atomic masses of hydrogen (H) and chlorine (Cl), which are 1.01 g/mol and 35.45 g/mol, respectively. Therefore, the molar mass of HCl is 36.46 g/mol.

To calculate the mass of hydrochloric acid needed, we can multiply the number of moles (10.00 moles) by the molar mass (36.46 g/mol):

Mass = number of moles × molar mass
Mass of HCl = 10.00 moles × 36.46 g/mol

Thus, the mass of hydrochloric acid needed to react with 5.00 moles of zinc is 364.6 g.

The equation tells you how many moles of HCl to use

convert that to grams