A bullet mass of 0.05kg is fired horizontally into a 10kg block which is free to move with velocity of 0.5m/s after the impact. Find the velocity with which the bullet hits the body

Please, can someone urgently help me solve this?

original momentum = 0.05 v

final momentum = (0.05 + 10.00) * 0.5
There are no external forces so
0.05 v = 10.05 * 0.5
solve for v says Newton #1

To find the velocity with which the bullet hits the body, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Let's denote the velocity of the bullet as v_bullet and the velocity of the block after the impact as v_block.

The momentum before the collision is given by the product of the mass and the velocity:

Momentum_before = mass_bullet * velocity_bullet = 0.05 kg * v_bullet

The momentum after the collision is given by:

Momentum_after = (mass_bullet + mass_block) * velocity_block = (0.05 kg + 10 kg) * 0.5 m/s

According to the principle of conservation of momentum, the momentum before the collision is equal to the momentum after the collision:

Momentum_before = Momentum_after

0.05 kg * v_bullet = 10.05 kg * 0.5 m/s

Now we can solve for v_bullet:

v_bullet = (10.05 kg * 0.5 m/s) / 0.05 kg
v_bullet = 10.05 m/s

Therefore, the velocity with which the bullet hits the body is 10.05 m/s.

To find the velocity with which the bullet hits the body, we can use the principle of conservation of momentum.

The principle of conservation of momentum states that the total momentum before an event is equal to the total momentum after the event, as long as no external forces are acting on the system.

In this case, we have two objects involved: the bullet and the block. Let's denote the velocity of the bullet before the impact as v_bullet and the velocity of the block after the impact as v_block.

The momentum of an object is given by the product of its mass and velocity: momentum = mass * velocity.

Before the impact, the bullet has momentum and the block has zero momentum since it is initially at rest. Therefore, the total momentum before the impact is:

total momentum before = momentum of bullet + momentum of block
= mass of bullet * velocity of bullet + mass of block * velocity of block
= (0.05 kg) * v_bullet + (10 kg) * 0

Since we know that the bullet stops completely after the impact, the velocity of the bullet after the impact is 0. Therefore, the total momentum after the impact is only due to the block and is given by:

total momentum after = momentum of block
= mass of block * velocity of block
= (10 kg) * (0.5 m/s)

According to the conservation of momentum principle, these two momenta should be equal:

total momentum before = total momentum after

(0.05 kg) * v_bullet + (10 kg) * 0 = (10 kg) * (0.5 m/s)

Simplifying the equation, we have:

(0.05 kg) * v_bullet = (10 kg) * (0.5 m/s)

Dividing both sides of the equation by 0.05 kg, we get:

v_bullet = (10 kg) * (0.5 m/s) / (0.05 kg)

Simplifying further, we have:

v_bullet = 100 m/s

Therefore, the velocity with which the bullet hits the body is 100 m/s.