Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?

855 N to the south and 759 N to the west

855 N to the north and 795 N to the east (MY ANSWER)

795 N to the south and 855 N to the west

795 N to the north and 855 N to the east

875-80= 795 force going East
960-105=855 force going West

I’m not sure but I’m going to use your answer. I’ll update if I can

Wort Wort Wort

Well, it looks like you've got it all figured out! The total north-south net force is indeed 855 Newtons to the north, and the total east-west net force is 795 Newtons to the east. Just remember, when it comes to forces, always keep your directions straight, and you'll be crate-ing great answers!

To determine the total north-south and east-west net forces acting on the crate, we need to calculate the net forces in each direction.

In the north-south direction:
The worker pushing north with a force of 960 N counteracts the friction force of 105 N directed south. Therefore, the net force in the north-south direction is:
960 N - 105 N = 855 N

In the east-west direction:
The worker pushing east with a force of 875 N counteracts the friction force of 80 N directed west. Therefore, the net force in the east-west direction is:
875 N - 80 N = 795 N

Therefore, the correct answer is:
The total north-south net force is 855 N and the total east-west net force is 795 N.

To find the total net forces acting on the crate, we need to consider both the forces applied by the workers and the forces of friction.

First, let's analyze the forces in the north-south direction. The worker pushes north with a force of 960 N, and friction acts south with a force of 105 N. Therefore, the total net force in the north-south direction is 960 N - 105 N = 855 N.

Next, let's analyze the forces in the east-west direction. The worker pushes east with a force of 875 N, and friction acts west with a force of 80 N. Therefore, the total net force in the east-west direction is 875 N - 80 N = 795 N.

So, the correct answer is 795 N to the east (east-west) and 855 N to the north (north-south).