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Hypochlorous acid, HOCl, is a weak acid with Ka = 3.0 × 10-8. Calculate the

pH of a 0.0125 M solution of HOCl.

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  1. ....................HOCl ==> H^+ + OCl^-
    I..................0.0125M.....0...........0
    C................ - x...............x...........x
    E................0.0125-x.......x...........x
    Ka = 3.0 × 10-8 = (H^+)(OCl^-)/(HOCl)
    Substitute the E line into the Ka expression and solve for x = (H^+)
    Then pH = -log(H^+)
    Post your work if you get stuck.

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