Okay so I have 4 questions

1.
Which list contains only common multiples of 3 and 6?
A. 3,6,9,12,15
B. 6,12,18,24,30
C. 20,30,40,50
D. 1,2,3,6

2.
I figured it out after writing this and didn't feel like changing it

3.
Which list contains the first 5 multiples of 7?
A. 28,35,42,49,56
B. 14,21,28,35,42
C. 7,14,21,28,35
D. 16,24,32,40,48

4.
What is the least common multiple that could be used to find the common denominator for the fractions 1/8 and 2/6?
A. 16
B. 8
C. 24
D. 48

Note: Please just leave either A, B, C, or D for the answers

#3

which list starts with a 7, and then all following are divisible by 7 ?

#4
8 = 2*2*2
6 = 2*3
So we need a number containing all those factors, I ge
2*2*2*3 = ....

Sure, here are the answers:

1. The correct answer is B. 6,12,18,24,30.

2. No action needed as you mentioned you figured it out.

3. The correct answer is C. 7,14,21,28,35.

4. The correct answer is C. 24.

1. To find the list that contains only common multiples of 3 and 6, you need to identify the numbers that are divisible by both 3 and 6. One way to do this is by finding the multiples of each number and comparing them. Let's break it down:

- First, let's find the multiples of 3: 3, 6, 9, 12, 15...
- Now, let's find the multiples of 6: 6, 12, 18, 24, 30...

Comparing the lists, we can see that the only numbers that appear in both lists are 6 and 12. Therefore, the correct answer is A.

3. Similar to the previous question, you need to find the first 5 multiples of 7. Let's identify them:

- The multiples of 7 are: 7, 14, 21, 28, 35...
- Comparing these multiples, we can see that option C, which contains 7, 14, 21, 28, 35, is the correct answer.

4. To find the least common multiple (LCM) that can be used as the common denominator for the fractions 1/8 and 2/6, you need to find the smallest number that is divisible by both 8 and 6. Let's calculate the multiples:

- Multiples of 8: 8, 16, 24, 32, 40, 48...
- Multiples of 6: 6, 12, 18, 24, 30, 36...

Comparing these multiples, we find that the smallest number that appears in both lists is 24. Therefore, the correct answer is C.